Comparing F(a) and F(n) for a Tennis Ball-Racquet Collision

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In the discussion about the forces during a tennis ball-racquet collision, participants clarify the definitions of F(a) as the applied force and F(n) as the normal force. It is established that the force exerted on the ball by the racquet equals the force exerted on the racquet by the ball, in accordance with Newton's third law. The tennis ball accelerates more than the racquet due to its lower mass and the racquet being anchored by the player's arm. Newton's second law is referenced to explain the differing accelerations of the ball and racquet. Overall, the conversation emphasizes the relationship between the forces and the resulting accelerations during the collision.
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Homework Statement




for an FDB of an tennis ball hitting the racquet. Is the F(a)=F(n) or is F(a) larger then F(n).



The Attempt at a Solution



I think that F(a) = F(n). According to Newton's second law, they both receive the same force, however since the tennis ball has less mass, it receiver a larger acceleration then the tennis racquet (which is also anchored by the player's arm).

Im pretty sure I am right, but it's always good to be sure.
 
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vysis said:

Homework Statement




for an FDB of an tennis ball hitting the racquet. Is the F(a)=F(n) or is F(a) larger then F(n).
What do you mean by F(a) and F(n)?

The Attempt at a Solution



I think that F(a) = F(n). According to Newton's second law, they both receive the same force, however since the tennis ball has less mass, it receiver a larger acceleration then the tennis racquet (which is also anchored by the player's arm).
This is not Newton's 2nd law.
Im pretty sure I am right, but it's always good to be sure.
Draw a FBD of the ball, not the racquet. What forces act on the ball? The problem is not asking for acceleration.
 
PhanthomJay said:
What do you mean by F(a) and F(n)?

F(a) = applied force
F(n) = Normal force

This is not Newton's 2nd law.
umm, yea sry. I was typing a bit too quickly. Third and Second law.

Draw a FBD of the ball, not the racquet. What forces act on the ball? The problem is not asking for acceleration.
nono, i mean if a tennis racquet was to hit a tennis ball. Would the applied force and normal force be equal or would applied force be larger?
 
Neglecting the weight of the tennis ball, when the racquet hits the ball, there is only one force acting on the ball...the force of the racquet on the ball, which i guess you are calling an applied force, F(a),which is fine. Now by F(n), I think you mean the force of the ball on the racquet?
 
yea, the equal and opposite force excerted on the racquet stated by the 3rd law.
 
vysis said:
yea, the equal and opposite force excerted on the racquet stated by the 3rd law.
Well, you just answered your question!
 
lol, so to sum it up:

force exerted on ball = force exerted on racquet.
However, ball flies away extremely quickly and racquet doesn't is becaue racquet is heavier and therefore according to Newton's second low, it doesn't accelerate as much (and also since the racquet is anchored to the player's hands)
 
vysis said:
lol, so to sum it up:

force exerted on ball = force exerted on racquet.
Correct! (equal but opposite in direction...force exerted on ball by racquet = force exerted on racquet by ball)
However, ball flies away extremely quickly and racquet doesn't is becaue racquet is heavier and therefore according to Newton's second low, it doesn't accelerate as much (and also since the racquet is anchored to the player's hands)
Sort of. The acceleration of the ball will be in the direction of the average impulse force (which you refer to as the applied force), in accordance with Newton 2. The racquets acceleration (deceleration) is a much more complex phenomenon because of the additional varying force acting on it from the player, and the impulsive nature of the event, but it is still Newton 2 at work.
 
Last edited:
thank you so much
 

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