Comparing SHM of Two Identical Masses on Springs

AI Thread Summary
The discussion focuses on comparing the simple harmonic motion (SHM) of two identical masses on springs with different spring constants. A higher spring constant indicates a stiffer spring, which affects the frequency of oscillation. The relationship between spring constant and frequency is established through the formula for the time period of SHM, where a stiffer spring results in a shorter time period and thus a higher frequency. Participants express confusion about how these concepts relate to the graphical representation of harmonic motion. Understanding these relationships is crucial for analyzing the behavior of oscillating systems.
SherlockIsReal
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Homework Statement


Compare the simple harmonic motion of two identical masses oscillating up and down on springs with different spring constants.

Homework Equations


F = -kx

The Attempt at a Solution


Okay, so I understand that the higher the spring constant, the harder it is to compress the spring. But I don't know how to relate that to the graph of harmonic motion. If the spring constant is higher , does that mean that the amplitude is lower? Or that the frequency is shorter?
 
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SherlockIsReal said:
that the frequency is shorter?
Do have any equation relating time period and spring constant.
 
SherlockIsReal said:
Or that the frequency is shorter?
For one thing, frequency is cycles per second (or radians per second, for angular frequency). Frequencies could be described as higher or lower; wavelengths, as longer or shorter.

How does frequency relate to spring constant? Look it up!
 
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