Comparing thermo dynamic processes

  • Thread starter Thread starter icelated
  • Start date Start date
  • Tags Tags
    Dynamic Thermo
Click For Summary
SUMMARY

The discussion focuses on the thermodynamic processes involving 1.2 mol of an ideal gas with a specific heat ratio (gamma) of 1.67, initially at a pressure of 3.60 x 105 Pa and a temperature of 300 K, undergoing compression to half its volume. The work done on the gas is calculated for three processes: isothermal, adiabatic, and isobaric. The absolute value of the change in internal energy is greatest during the isobaric process and least during the isothermal process, as the internal energy change is zero at constant temperature.

PREREQUISITES
  • Understanding of ideal gas laws and equations (PV = nRT)
  • Knowledge of thermodynamic processes: isothermal, adiabatic, and isobaric
  • Familiarity with the concept of internal energy and its relation to temperature
  • Basic calculus for calculating work done in thermodynamic processes
NEXT STEPS
  • Study the derivation of work done in isothermal processes for ideal gases
  • Learn about the first law of thermodynamics and its application in different processes
  • Explore the concept of internal energy in detail, particularly for adiabatic processes
  • Investigate real gas behavior and deviations from ideal gas laws under various conditions
USEFUL FOR

This discussion is beneficial for students studying thermodynamics, physics enthusiasts, and professionals in engineering fields who require a solid understanding of gas behavior under different thermodynamic processes.

icelated
Messages
8
Reaction score
0

Homework Statement



in a cylinder, 1.2 mol of an ideal gas, gamma = 1.67 initially at 3.60 x10^5 pa
and 300k, is compressed until the volume is halved.

I need help with 1) c
and
2)

Compute work done on the gas if the compression is:

1)

a) isothermal
b) adiabatic
c) isobaric

2) in which case is the absolue value of the change in internal energy of the gas the greatest? least?

Homework Equations



I think i have a and b worked out.

The Attempt at a Solution



for c) would this be the correct approach?

is this part correct?

V1 = ?
V2 = 1/2V1

w = p(V2 - V1)
w = p(1/2v - v)

pv = nrt

w = -1/2nrt?

2) greatest is isobaric because?
least is isothermal because delta u =0 constant temp and temp is related to change in internal energy.
 
Physics news on Phys.org
How can the gas get compressed if the process is isobaric? What other property must change?
 
the volume is being compressed. But, th pressure remains constant so the area of work is less than the other 2 processes? Adiabatic is the most?
 

Similar threads

To find total work done from multiple reversible processes
  • · Replies 3 ·
Replies
3
Views
2K
How do I calculate work and heat in a PV diagram for an ideal monoatomic gas?
  • · Replies 11 ·
Replies
11
Views
2K
Calculate Work (w) for Isothermal Gas Expansion/Compression
  • · Replies 4 ·
Replies
4
Views
3K
Is the Work Done by the Piston on the Gas Counted Twice in PV Diagrams?
  • · Replies 5 ·
Replies
5
Views
2K
Thermo: isothermal, reversible expansion of ideal gas
  • · Replies 4 ·
Replies
4
Views
3K
Work done in adiabatic process vs work done in isothermal
  • · Replies 2 ·
Replies
2
Views
3K
Thermodynamics First Law Question
  • · Replies 4 ·
Replies
4
Views
3K
Thermal efficiency of the engine in a PV diagram
  • · Replies 2 ·
Replies
2
Views
3K
Work done in thermodynamic process
  • · Replies 18 ·
Replies
18
Views
6K
Isobaric Compression: Homework Help for Ideal Gas Laws
  • · Replies 8 ·
Replies
8
Views
12K