Complete the group as isomorphic

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1. Complete the following table to obtain a Group, G, that is isomorphic to Z4
2. Complete the same table to obtain a Group, H, that is NOT isomorphic to Z4

*| a b c d

a|
b|
c|
d|


I tried to complete the group as isomorphic, can anyone tell me if this is correct?

*| a b c d

a| a a a a
b| a b c d
c| a c a c
d| a d c b

And here is my attempt at part to as if it is not an isomorphism


*| a b c d

a| a b c d
b| b c d a
c| c d a b
d| d a b c
 
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Anarchy6k2 said:

*| a b c d

a| a a a a
b| a a a a
c| a a a a
d| a a a a
You're saying that this is the multiplication table for a group? What's the inverse of b?
 
:(

All I can say is LOL you might want to work on the table with all a's in it. It has to follow group properties. I hope that's not the grade you want in this class.
 
ok here

ok now that you got rid of all those crazy a's here is what I got.

Part 1. isomorphic to Z4
abcd
bcda
cdab
dabc

part 2. not isomorphic to Z4
abcd
badc
cdab
dcba

Anyone else get this?
 
Thanks, I was talking it over with some friends and we all got the same thing. Thanks for the assistance haha now I can definatly get an A ^_^
 
Yes, all groups of order 4 are either isomorphic to Z4 or the Klein 4 group.

CrazyCalcGirl- please do NOT give complete answers in the homework section.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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