- #1
danielle36
- 29
- 0
I'm supposed to use the method of completeing the square to write an equation in the form [tex] y = a(x - p)^{2} + q [/tex].
Here's one of the equations: [tex] y = x^{2} + 6x [/tex]
and another: [tex] y = -2x^{2} + 8x + 5 [/tex]
I really don't know where to start, which is why I can't include any work... The main problem here is I don't know how to get the equation in the [tex] (x - p)^{2} [/tex] format. I can complete the square but its the - sign that's throwing me off.
If someone could just explain how to go about doing this it would be greatly appreciated.
Here's one of the equations: [tex] y = x^{2} + 6x [/tex]
and another: [tex] y = -2x^{2} + 8x + 5 [/tex]
I really don't know where to start, which is why I can't include any work... The main problem here is I don't know how to get the equation in the [tex] (x - p)^{2} [/tex] format. I can complete the square but its the - sign that's throwing me off.
If someone could just explain how to go about doing this it would be greatly appreciated.