Completing the squares of a multivariable function

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SUMMARY

The discussion focuses on the method of completing the square for the multivariable function defined by the equation x² + y² + 2xy - 2x - 2y + 43 = 0. The user successfully transforms the equation into the form ((x + y) - 1)² + 42, demonstrating a clear understanding of the technique. The user seeks alternative methods for completing the square, indicating a desire for optimization or simplification. However, the response suggests that the presented method is already efficient and aesthetically pleasing.

PREREQUISITES
  • Understanding of quadratic equations
  • Familiarity with algebraic manipulation
  • Knowledge of multivariable functions
  • Experience with completing the square technique
NEXT STEPS
  • Explore alternative methods for solving multivariable equations
  • Learn about the geometric interpretation of completing the square
  • Study the implications of completing the square in optimization problems
  • Investigate the use of completing the square in calculus for finding critical points
USEFUL FOR

Students studying algebra, mathematics educators, and anyone interested in enhancing their skills in solving multivariable equations through completing the square.

pondzo
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Homework Statement



completing the squares; ## x^2+y^2+2xy-2x-2y+43 = 0##

The Attempt at a Solution



I did it as follows, but i would like to know if there is a different 'nicer' method to complete it;

## x^2 + y^2 + 2xy − 2x − 2y + 43 ##

## = (x + y)^2 − 2x − 2y + 43 ##

## = (x + y)^2 − 2(x + y) + 43 ##

## = (x + y)^2 − 2(x + y) + 1 + 42 ##

## = ((x + y) − 1)^2 + 42 ##
 
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pondzo said:

Homework Statement



completing the squares; ## x^2+y^2+2xy-2x-2y+43 = 0##

The Attempt at a Solution



I did it as follows, but i would like to know if there is a different 'nicer' method to complete it;

## x^2 + y^2 + 2xy − 2x − 2y + 43 ##

## = (x + y)^2 − 2x − 2y + 43 ##

## = (x + y)^2 − 2(x + y) + 43 ##

## = (x + y)^2 − 2(x + y) + 1 + 42 ##

## = ((x + y) − 1)^2 + 42 ##
That looks plenty "nice" to me !
 

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