Completing the Square with Coefficient on X^2

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Homework Help Overview

The discussion revolves around the problem of completing the square for a quadratic equation involving multiple variables, specifically focusing on the variations of the equation with different signs on the degree 2 terms. The original poster expresses difficulty in handling negative coefficients during this process.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to complete the square for the negative coefficient of the y-term and questions how to handle the sign of the coefficient when rewriting the equation. Other participants suggest methods for balancing the equation and emphasize the importance of tracking added quantities.

Discussion Status

Participants are actively engaging with the original poster's questions, providing guidance on how to approach the completion of the square with negative coefficients. There is a collaborative effort to clarify the process, though no consensus or final solution has been reached.

Contextual Notes

The original poster is working within the constraints of a homework assignment that requires finding and describing different quadric surfaces from the given equation, which adds complexity to the discussion.

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Homework Statement



Consider all possible surfaces that can be formed from the variations of

\[PlusMinus]x^2\[PlusMinus]4y^2\[PlusMinus]z^2+2x+8y+6z==-6,

that is, find and describe all the different quadric surfaces you can make from this equation by using different signs on the degree 2 terms. For each one, find the standard form of the equation.

I am having problems completing the square when the coefficient is negative.

The Attempt at a Solution



For the case where the y-coefficient is negative:

(x^2 + 2x + 1) + (-4y^2 + 8y + _ ) + (z^2 +6z + 9) = -6 + 1 + _ + 9

dividing by -4 gives: (y^2 - 2y + _ )

Adding (b/2a)^2: (y^2 - 2y + 1)

Condensing: (y - 1)^2

Now, does the coefficient 4 come back as positive or negative, as in
4(y - 1)^2 or -4(y - 1)^2

Also, when adding to the other side of the equation, does the -4 multiply to the added quantity?

Thanks for any help
 
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(-4y2 + 8y )
= -(4y2 - 8y + __) + something

You're going to add a positive number inside the parentheses, but you have really added a negative number, so to keep the expression in balance, add the positive of that negative number.

Make sense?
 
What else you should do to make your life simpler is to bring out the coefficient on the 2nd degree term so that you have
-4(y2 - 2y + __) + something

Just keep track of what you really added to the overall expression.
 
Okay, thanks for helpin me out
 

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