Completing the Square with Coefficient on X^2

In summary, the conversation discusses finding and describing all possible quadric surfaces that can be formed from the given equation by using different signs on the degree 2 terms. The solution involves completing the square and condensing the equation, with a focus on handling negative coefficients. It is suggested to bring out the coefficient on the 2nd degree term to simplify the process.
  • #1
fuzzface89
2
0

Homework Statement



Consider all possible surfaces that can be formed from the variations of

\[PlusMinus]x^2\[PlusMinus]4y^2\[PlusMinus]z^2+2x+8y+6z==-6,

that is, find and describe all the different quadric surfaces you can make from this equation by using different signs on the degree 2 terms. For each one, find the standard form of the equation.

I am having problems completing the square when the coefficient is negative.

The Attempt at a Solution



For the case where the y-coefficient is negative:

(x^2 + 2x + 1) + (-4y^2 + 8y + _ ) + (z^2 +6z + 9) = -6 + 1 + _ + 9

dividing by -4 gives: (y^2 - 2y + _ )

Adding (b/2a)^2: (y^2 - 2y + 1)

Condensing: (y - 1)^2

Now, does the coefficient 4 come back as positive or negative, as in
4(y - 1)^2 or -4(y - 1)^2

Also, when adding to the other side of the equation, does the -4 multiply to the added quantity?

Thanks for any help
 
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  • #2
(-4y2 + 8y )
= -(4y2 - 8y + __) + something

You're going to add a positive number inside the parentheses, but you have really added a negative number, so to keep the expression in balance, add the positive of that negative number.

Make sense?
 
  • #3
What else you should do to make your life simpler is to bring out the coefficient on the 2nd degree term so that you have
-4(y2 - 2y + __) + something

Just keep track of what you really added to the overall expression.
 
  • #4
Okay, thanks for helpin me out
 

Related to Completing the Square with Coefficient on X^2

What is completing the square with coefficient on X^2?

Completing the square with coefficient on X^2 is a method used in algebra to solve quadratic equations. It involves manipulating the equation to create a perfect square trinomial, which can then be easily solved.

Why is completing the square with coefficient on X^2 useful?

Completing the square with coefficient on X^2 is useful because it allows us to solve quadratic equations that cannot be solved using other methods, such as factoring or the quadratic formula. It also helps us find the vertex of a parabola, which is useful in many real-world applications.

How do you complete the square with coefficient on X^2?

To complete the square with coefficient on X^2, follow these steps:
1. Move the constant term to the right side of the equation.
2. Divide the coefficient on X^2 by 2, square it, and add it to both sides of the equation.
3. Factor the perfect square trinomial on the left side of the equation.
4. Simplify the right side of the equation.
5. Take the square root of both sides of the equation.
6. Solve for X.

What if the coefficient on X^2 is negative?

If the coefficient on X^2 is negative, you can still complete the square using the same steps as before. However, when taking the square root, you must remember to include a plus or minus sign, as the square root of a negative number is imaginary. This will result in two possible solutions for X.

Can completing the square with coefficient on X^2 be used on all quadratic equations?

Yes, completing the square with coefficient on X^2 can be used on all quadratic equations, but it may not always be the most efficient method. It is useful when the equation cannot be factored or when the coefficient on X^2 is not 1.

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