Complex Analysis: Inverse function is holomorphic

In summary, the conversation is about proving the holomorphicity of the inverse function g of a univalent holomorphic function f in an open connected set G. The problem is from Sarason, page 44, Exercise IV.14.1. The problem requires showing that if f(G) is open and g is continuous, then g is also holomorphic. The person has tried three different methods but failed and is seeking further insight. The professor recommended looking at the calculus proof of the derivative of an inverse and using the definition of differentiability and continuity to prove g is holomorphic.
  • #1
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Homework Statement


The problem is from Sarason, page 44, Exercise IV.14.1.

Let f be a univalent holomorphic function in the open connected set G, and let g be the inverse function.
Assume that f(G) is open, that g is continuous, and that [tex]f\prime\neq 0\forall z\in G[/tex]. Prove g is holomorphic.

Homework Equations


The Attempt at a Solution


I've tried 3 different methods, failing with each. I'd appreciate any insight into the problem.
My professor recommended looking at the calculus proof of the derivative of an inverse, and the following:
Start with [tex]w_{0}\in f(G)[/tex], and with h small, look at [tex]\frac{(g(w_{0}+h)-g(w_{0}))}{h}[/tex].

Because [tex]f(G)[/tex] is open, we know there is a [tex]\delta>0\ni \left|h\right|<\delta[/tex] gives us [tex]w_{0}+h\in f(G)[/tex].
So with h that small, we have [tex]w_{0}+h=f(z)[/tex] for some [tex]z \in
G[/tex].
 
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  • #2
You're off to a good start. I'd suggest also defining [itex]z_0\equiv f^{-1}(w_0)[/itex] and then using that along with the other defined variables to write out the definitions, in terms of [itex]\epsilon[/itex]s and [itex]\delta[/itex]s, of f being differentiable, and f' and g' being continuous.
 

1. What is the inverse function in complex analysis?

The inverse function in complex analysis is a function that undoes the effect of another function. In other words, if f(z) is a complex function, then its inverse function would be denoted as f-1(z) and it would reverse the output of f(z).

2. What does it mean for an inverse function to be holomorphic?

A holomorphic inverse function is one that is analytic in a region of the complex plane. This means that it possesses a derivative at every point in that region and that derivative is also continuous. Essentially, a holomorphic inverse function is a complex function that is differentiable and behaves smoothly in a certain area.

3. How is the holomorphicity of an inverse function related to the holomorphicity of its original function?

The holomorphicity of an inverse function is directly related to the holomorphicity of its original function. If the original function is holomorphic in a region, then its inverse function will also be holomorphic in a corresponding region. This is because the inverse function is essentially the original function being run in reverse, and the properties of holomorphicity are preserved in this process.

4. Can an inverse function be holomorphic in one region and not in another?

Yes, it is possible for an inverse function to be holomorphic in one region and not in another. This is because the properties of holomorphicity can vary depending on the region in which the function is being analyzed. A function may be holomorphic in one region but not in another due to the presence of singularities or branch points.

5. What is the importance of inverse functions in complex analysis?

Inverse functions play a crucial role in complex analysis as they allow for the manipulation and understanding of complex functions. They also provide a way to solve equations and problems that involve complex functions. Additionally, the concept of holomorphicity and inverse functions is fundamental in the study of complex analysis and has many applications in mathematics and other fields such as physics and engineering.

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