Complex integration over a curve

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Homework Statement


Compute ∫C (z+i)/(z3+2z2) dz

Homework Equations


C is the positively orientated circle |z+2-i|=2


The Attempt at a Solution


I managed to solve a similar problem where the circle was simply |z|=1, with the centre at the origin converting it to z=e with 0≤θ2∏. I'm not sure how to go forward with the centre in another position.

If I want to parametise the equation for z for the circle, then I get two different equations for z because of the possibility that it could be + or - because of the absolute value.

I haven't gotten very far - could anyone help start me off on this!
 
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|z+ 2- i|= 2 is the same as |z- (-2+ i)|= 2 and is the circle with center at -2+ i and radius 2 with \theta going from 0 to 2\pi. Yes, we can write the circle with center at 0 and radius 1 as z= e^{i\theta}. The circle with center at 0 and radius 2 is z= 2e^{i\theta}. Finally, the circle with center -2+ i and radius 2 is z= -2+ i+ 2e^{i\theta}
 
Thank you, that helps!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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