Complex variables questions, limits and bounds

futurebird
Messages
270
Reaction score
0
If I have a function f(z) such that limit z --> infinity is finite what do I know about that function?

Is it "bounded" or am I still confused about what "bounded" means?
 
Physics news on Phys.org
Bounded means that |f(z)| stays less than some finite value B for ALL z. So, no. For example,

\lim_{z->\infty} \frac{1}{z} = 0

but f(z)=1/z is not bounded (it blows up at z=0).
 
Okay. That makes sense.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Back
Top