Complicated Curve Sketch and Derivative Computation (Calc I)

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SUMMARY

The discussion focuses on solving calculus problems involving the fundamental theorem of calculus, limits, and absolute value functions. Participants clarify that slant asymptotes are not necessary for solving the given problems, emphasizing the importance of calculating limits as x approaches infinity. Specifically, the limits m = limx→∞(f(x)/x) and limx→∞(f(x) - mx) are critical for determining the behavior of the function. Additionally, it is established that when evaluating limits for large x, absolute value signs can be disregarded if the argument is positive.

PREREQUISITES
  • Understanding of the fundamental theorem of calculus
  • Knowledge of limits and their computation
  • Familiarity with absolute value functions
  • Basic principles of derivatives and their applications
NEXT STEPS
  • Study the fundamental theorem of calculus in detail
  • Learn how to compute limits at infinity
  • Explore the properties of absolute value functions in calculus
  • Practice derivative computation for piecewise functions
USEFUL FOR

Students in Calculus I, mathematics educators, and anyone seeking to improve their understanding of limits, derivatives, and the fundamental theorem of calculus.

ShangMing
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Homework Statement


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Homework Equations


Fundamental theorem of calculus.

The Attempt at a Solution


For the first problem, I'm completely lost. I've only worked with slant asymptotes for polynomials so finding the domain, range and intercepts is as far as I've gotten.

I'm not too great at absolute value functions either, so when I take the derivative, do I need to use two cases for positive and negative x when I'm finding intervals of increase/decrease, concavity, etc?

For the second question, I have absolutely no idea where to even begin.

Thanks PF
 
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You don't need to know anything about slant asymptotes to answer this question. All they're asking you is to calculate two limits:

m=\lim_{x\rightarrow \infty}{\frac{f(x)}{x}}

and once you've calculates that, you need to calculate

\lim_{x\rightarrow \infty}{f(x)-mx}


And don't worry about the absolute value. You take the limit to positive infinity. This means that your x will become very large, and in particular it will become larger then -2. This means that |x+2| becomes positive. So you can drop the absolute value signs.
 

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