1. The problem statement, all variables and given/known data Given the incline plane, see picture, a box is let loose, attached to a spring in a relaxed position, the box moves down 2.75 meters. The variables: incline is at 32 degrees, the friction coefficient is .125 and the mass of the box is 17.4 kg. The length it slides is 2.75 meters. Find the: spring constant (k) when friction is present? spring constant (k) when friction is not present? the velocity of the box when it is half way down the incline (so 1.375 meters)? 2. Relevant equations The teacher said that I could use conservation of energy to solve this and said that I could set it up in the following way Work(in)= (mass)(gravity)(height final -height initial)+(1/2)(mass)(vf^2-Vo^2)+(friction)(distance)+(1/2)(k)(change in spring position^2) I think that the Work goes to 0 , the Initial Velocity goes to 0, and the initial spring position is 0 ---- so---- 0= (mass)(gravity)(height final -height initial)+(1/2)(mass)(vf^2-0)+(friction)(distance)+(1/2)(k)(change in spring position^2) Is there a less cluttered way of solving this problem???? 3. The attempt at a solution The initial height should be (2.75)(sin32)? Right? The (distance) for the friction, and spring should be 2.75 because that is how far it goes? Does the final velocity also go to 0, I am not sure about that?