How to Solve x3+3x/3x2+1 using Componendo and Dividendo?

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The discussion revolves around solving the equation (x^3 + 3x) / (3x^2 + 1) = 341/91 using the Componendo and Dividendo method. The original poster expresses frustration after unsuccessfully applying both Componendo and Dividendo and the k-method, seeking assistance. Participants emphasize the importance of clarity in mathematical notation and suggest that the k-method is not applicable without proportional relationships. There is a call for the original poster to demonstrate their attempts to solve the problem to facilitate better guidance. The thread concludes with a suggestion to start a new thread if further help is desired.
physics kiddy
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Please solve this equation :

x3+3x/3x2+1 = 341/91

I applied Componendo and Dividendo, then k-method but could not solve this question. Please help me.
 
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physics kiddy said:
Please solve this equation :

x3+3x/3x2+1 = 341/91

I applied Componendo and Dividendo, then k-method but could not solve this question. Please help me.
Do you mean: (x3+3x)/(3x2+1) = 341/91 ?

Parentheses are important.
 
yes.
 
Did you try applying the rules of algebra?
 
no, i must use either componendo and dividendo or k-method. No algebra at all.
 
physics kiddy said:
no, i must use either componendo and dividendo or k-method. No algebra at all.
I doubt that many of us here even know what "componendo and dividendo" mean or what "k-method" means.

The first two are apparently Spanish or maybe Portuguese for combining and dividing.
 
physics kiddy,
Are you trying to solve for x, or are you substituting a value for x in order to evaluate the rational expression?
 
physics kiddy said:
Please solve this equation :

x3+3x/3x2+1 = 341/91

I applied Componendo and Dividendo, then k-method but could not solve this question. Please help me.

Hiii physics kiddy !

Try applying componendo and dividendo once more. I will guide you. :wink:

k-method cannot work here because there are no proportional relation given.
If there are relations like a,b,c and d are in continued proportion , then k-method can be applied.

You can even try cross-multiplying.
:wink:
 
sankalpmittal said:
Hiii physics kiddy !

Try applying componendo and dividendo once more. I will guide you. :wink:

k-method cannot work here because there are no proportional relation given.
If there are relations like a,b,c and d are in continued proportion , then k-method can be applied.

You can even try cross-multiplying.
:wink:

Please solve this question. I am tired of using componendo and dividendo but all my efforts go useless. I can't go any further. It would be very kind of you if you solve the question. Thanks again for the help.
 
  • #10
physics kiddy said:
Please solve this question. I am tired of using componendo and dividendo but all my efforts go useless. I can't go any further. It would be very kind of you if you solve the question. Thanks again for the help.

You need to show an attempt at the problem. Show us what you've tried.
 
  • #11
We don't dislike you enough to want to prevent you from learning! I am closing this thread. If you really want help, start a new thread showing what you have done.
 
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