Composition and the chain rule

Telemachus
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Homework Statement


I have a problem with the next exercise:

Given de function f(x,y)=\begin{Bmatrix} \displaystyle\frac{xy^2}{x^2+y^2} & \mbox{ if }& (x,y)\neq{(0,0)}\\0 & \mbox{if}& (x,y)=(0,0)\end{matrix} with \vec{g}(t)=\begin{Bmatrix} x=at \\y=bt \end{matrix},t\in{\mathbb{R}}

a) Find h=fog y \displaystyle\frac{dh}{dt} for t=0

The thing is that I've found that f isn't differentiable at (0,0). The partial derivatives exists at that point, I've found them by definition.

f_x(0,0)=0=f_y(0,0)

And then I saw if it was differentiable at that point.

\displaystyle\lim_{(x,y) \to{(0,0)}}{\displaystyle\frac{xy^2}{(x^2+y^2)^{3/2}}}

In the polar form it gives that this limit doesn't exists, so it isn't differentiable at that point. So I can't apply the chain rule there, right?

To ensure the differentiability of a composed function, both function must be differentiable. If one isn't, then the composition isn't differentiable at a certain point. Right?

Bye there, and thanks.
 
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Telemachus said:

Homework Statement


I have a problem with the next exercise:

Given de function f(x,y)=\begin{Bmatrix} \displaystyle\frac{xy^2}{x^2+y^2} & \mbox{ if }& (x,y)\neq{(0,0)}\\0 & \mbox{if}& (x,y)=(0,0)\end{matrix} with \vec{g}(t)=\begin{Bmatrix} x=at \\y=bt \end{matrix},t\in{\mathbb{R}}

a) Find h=fog y \displaystyle\frac{dh}{dt} for t=0

The thing is that I've found that f isn't differentiable at (0,0). The partial derivatives exists at that point, I've found them by definition.

f_x(0,0)=0=f_y(0,0)

And then I saw if it was differentiable at that point.

\displaystyle\lim_{(x,y) \to{(0,0)}}{\displaystyle\frac{xy^2}{(x^2+y^2)^{3/2}}}

In the polar form it gives that this limit doesn't exists, so it isn't differentiable at that point. So I can't apply the chain rule there, right?

To ensure the differentiability of a composed function, both function must be differentiable. If one isn't, then the composition isn't differentiable at a certain point. Right?

Bye there, and thanks.

Found this here course where they deal with the chainrule on two variable function...
http://www.math.oregonstate.edu/hom...lculusQuestStudyGuides/vcalc/chain/chain.html
 
Thank you Susanne
 
Telemachus said:
Thank you Susanne

You are welcome. I find it better to see worked through examples something to understand the methods and theory :)
 
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