Compressed spring on the ceiling.

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AI Thread Summary
A box with a mass of 1.0 kg is attached to a ceiling by a spring with a spring constant of 112.0 N/m and a relaxed length of 28.0 cm, initially compressed to 14.0 cm. The problem involves determining the distance below the ceiling where the box comes to rest after being released. The relevant equation used is mgh = mgy2 + 0.5k(y2)2, but the user struggles to apply it effectively. The discussion highlights the need for clarity in using energy conservation principles in spring-related problems. The solution requires further calculations to find the equilibrium position of the box.
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Homework Statement


A box of mass M = 1.0 kg is attached to the ceiling by a spring with spring constant k = 112.0 N/m. The spring has a relaxed length L = 28.0 cm. Initially the spring is compressed to a length L/2. If the box is released, at what distance below the ceiling will the box first be brought to rest by the spring?


Homework Equations


I don't know if this is correct, but I attempted to use an equation given by my teacher for an object falling onto a spring, which is like opposite of this problem.
mgh = mgy2 + .5k(y2)2


The Attempt at a Solution


I used the equation but pretty much went to a dead end >.<
 
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