Compton Scattering- finding photon wavelength

AI Thread Summary
The discussion revolves around a homework problem involving Compton scattering, where an electron collides with a photon, leading to a change in their momenta and energies. The user attempts to apply conservation of momentum and energy equations to find the initial wavelength of the incoming photon. They express concerns about their approach, particularly regarding the conservation of momentum and energy, and whether these principles are sufficient to solve for the initial wavelength. A suggestion is made to use a more accurate energy expression for the electron. The conversation highlights the complexities of applying relativistic equations in particle collisions.
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Homework Statement


An electron moving to the left at 0.8c collides with an incoming photon moving to the right. After the collision, the electron is moving to the right at 0.6c and an outgoing photon moves to the left. What was the wavelength of the incoming photon?

Homework Equations


p=γmv
Eγ=pc=h/λ

λ'-λ = (h/mec)(1-cosθ)

The Attempt at a Solution


*Defining left as positive*
I have the following expressions for the initial and final momentum of the system, and I set them equal to each other.

Pinitial= pe + pγ
Pi = -γimevei + Eγi/c
Pf = γfmevef - Ef/c

given Ei/c = h/λ

h/λ - γimevei = γfmevef - h/λ'

h(1/λ + 1/λ') = γfmevef + γimevei

I can plug in all the values for the electron and get some number, but I am still left with λ and λ'. I'm not sure if my approach is correct, but if it is, I don't see how I can find just λ (the initial wavelength).
 
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Is the total momentum the only quantity that is conserved?
 
Chandra Prayaga said:
Is the total momentum the only quantity that is conserved?
I presume energy would also be conserved, but writing out that expression also leaves me with λ and λ'

imevi2)/2 +mec2 - hc/λ = hc/λ' - (γfmevf2)/2 - mec2
 
Your expression for the energy of the electron is wrong
 
Would E= √(p2c2 + m02c4) be more accurate?
 
That is correct
 
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