MHB Compute the integral of the Cantor-Lebesgue function ∫_0^1〖F(x)〗 dm .

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The integral of the Cantor-Lebesgue function over the interval from 0 to 1 is 0 due to its singular nature, which results in a zero Lebesgue measure. To compute this integral, the Lebesgue integral definition is applied, involving the limit of sums of function values multiplied by the measure of intervals. As the function is singular, the measure of all intervals between points in the interval [0,1] is 0. Therefore, the integral evaluates to 0. This confirms the unique properties of the Cantor-Lebesgue function in relation to Lebesgue integration.
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How should I compute the integral of the Cantor-Lebesgue function ∫_0^1〖F(x)〗 dm?
 
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The integral of the Cantor-Lebesgue function is 0. This is due to the fact that the Cantor-Lebesgue function is a singular function and thus has a zero Lebesgue measure. To compute this integral, one can use the definition of the Lebesgue integral: ∫_0^1〖F(x)〗 dm = lim_{n→∞} ∑_i=1^n F(x_i)Δm_iwhere x_i are points in the interval [0,1] and Δm_i is the Lebesgue measure of the interval between them. Since the function is singular, all of the intervals between the points will have a measure of 0, so the integral will be 0.
 

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