Compute the Z-transform of a^{-n} and step function

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SUMMARY

The Z-transform of the sequence x[n] = (0.5)^{-n} * u[n-1] is computed using the formula x(z) = ∑_{n=1}^∞ (0.5)^{-n} * z^{-n}. The summation begins at n = 1 due to the unit step function u[n-1]. The expression simplifies to x(z) = ∑_{n=1}^∞ (2z^{-1})^{n}, which can be evaluated using the geometric series formula. The Region of Convergence (ROC) must be determined, noting that the series diverges for certain values, indicating that the Z-transform may not exist for all z.

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  • Understanding of Z-transform for discrete time signals
  • Familiarity with geometric series and convergence criteria
  • Knowledge of unit step functions in signal processing
  • Basic skills in manipulating infinite series
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  • Explore the implications of ROC in Z-transform analysis
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Homework Statement


Compute the Z-transform of

[tex]x[n] = (0.5)^{-n} * u[n-1][/tex]

And find the ROC (Region of Convergence)

Homework Equations


Z-Transform for discrete time
[tex]x(z) = \sum_{n=0}^\infty x[n] * z^{-n}[/tex]

The Attempt at a Solution



To solve this, I used the definition of Z-transform

[tex]x(z) = \sum_{n=1}^\infty (0.5)^{-n} * z^{-n}[/tex]

Note that the summation starts from n = 1 due to the time shift to the right by 1.

Simplifying this, we get

[tex]x(z) = \sum_{n=1}^\infty (0.5z)^{-n}[/tex]

Here's where I'm confused as hell. Apparently, we can't apply the geometric series to simplify this further since the expression is powered to the negative n.

Furthermore, what's contradicting about this problem is that the series diverges. Does this indicate that the z-transform does not exist at all?

Any help will be appriciated.
 
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Try a little rewrite:

[tex]x(z) = \sum_{n=1}^\infty (0.5^{-1}z^{-1})^{n}[/tex] or

[tex]x(z) = \sum_{n=1}^\infty (2z^{-1})^{n}[/tex] Now use your geometric series...
 

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