Compute Torque About Point A - 3 SF

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The discussion focuses on calculating the torque about point A for three forces, particularly F3. The key equation for torque is identified as Torque = Force * Distance * sin(theta). Participants clarify that the distance (r) should be the direct line from the force to point A, and using the hypotenuse of the triangle is appropriate. The angle for the torque calculation should be determined based on the position vector and the force vector, and breaking the force into x and y components can simplify the calculation. Overall, the conversation emphasizes understanding the relationship between force, distance, and angle in torque calculations.
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[SOLVED] Torque Question

Homework Statement



See diagram for problem

additional instructions
--------------------
For each of the three forces shown, compute the moment (N m, + CCW) about point A. Assume 3 SF for all numbers.

I am trying to solve for the moment(torque) of F3


Homework Equations



Force * (Distance between force and point A) * sine(theta)??


The Attempt at a Solution



too many to name.
 

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Peter2288 said:

Homework Equations



Force * (Distance between force and point A) * sine(theta)??




That's it! Problem over right there. Tounet = F.r.sinX. Add the torques seperately, one by one.
 
For force 3, the r value is supposed to be the direct line between it and the point of pivot right? Do I use the hypotenuse of the triangle for the r value? Also what angle do I use (arctan (3 / 4)??), and am I supposed to somehow break up the force into x and y components? I've tried some of this stuff, but none of it seemed to work. Thanks for your time.
 
Last edited:
Peter2288 said:
For force 3, the r value is supposed to be the direct line between it and the point of pivot right?
Right.
Do I use the hypotenuse of the triangle for the r value?
Sure.
Also what angle do I use (arctan (3 / 4)??),
When using r F \sin\theta, the angle is the angle between the position vector and the force vector.
and am I supposed to somehow break up the force into x and y components?
You can always break a force into its components and then find the torque for each component and add them. (That would be much quicker, especially if you realize that r \sin\theta is the perpendicular distance to the line of the force.)
 
Thanks guys.
 
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