Computing a Line Integral: Stokes' Thm

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Homework Statement



Compute the line integral of v = 6i + yz^2j + (3y + z)k along the path (0,0,0) -> (0,1,0) -> (0,0,2) -> (0,0,0). Check your answer using Stokes' Thm

Homework Equations





The Attempt at a Solution



I've tried breaking into three pieces. The first with dx = dz = 0, second dx = 0 and third dx = dy = 0. The solution is given as 8/3 but I can't seem to come up with that. Do I have to parametrize the curve or what?
 
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Well I was able to do it by paramatrizing the 3 paths individually. A little tedious, but given that you can't use Stokes' theorem except to check your answer, it's the best you can do. The paths are all straight lines. Perhaps you could use green's theorem here, since the path lies on a plane and is closed, but the function you're taking the path integral of has 6i in it.
 
Ok, I managed to get it. Thanks :smile:
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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