Concave Mirror Image Magnification Calculation

AI Thread Summary
To determine the object position for a concave mirror with a focal length of 33.5 cm that produces an upright image five times the size of the subject, the magnification equation m = -di/do is used. The relationship between object distance (do), image distance (di), and focal length (f) is given by the formula (1/di) + (1/do) = 1/f. The initial attempt incorrectly assumes di is 5 cm, which leads to confusion in calculations. By expressing di in terms of do and magnification, one can substitute into the focal length equation to find the correct values. This approach clarifies the relationship needed to solve the problem accurately.
Kris1120
Messages
42
Reaction score
0

Homework Statement



A concave mirror has a focal length of
33.5 cm.
Determine the object position for which the
resulting image is upright and five times the
size of the subject.
Answer in units of cm.

Homework Equations



m=-(di/do)

(1/di)+(1/do)= 1/f

The Attempt at a Solution



1/do = (1/35) - (1/5) = -0.170149
do= -5.87719
 
Physics news on Phys.org
1/do = (1/35) - (1/5) = -0.170149

You're assuming di is 5 cm here, which isn't true.
 
I don't know how to solve for one without the other?
 
You can write di in terms of do and m (using the magnification equation you had).

Then, substitute that for di in the "1/f=..." equation.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top