Concentric Spheres Capacitance Question- How to use area

AI Thread Summary
To calculate the capacitance of concentric metal shells, the appropriate formula differs from that of parallel-plate capacitors. The capacitance of spherical capacitors requires a specific formula that accounts for the geometry of the shells. The area used in the capacitance calculation should correspond to the smaller shell, as it defines the effective area for the capacitor. The assumption of equal charge is relevant when using the formula C=Q/deltaV, but the capacitance formula itself does not directly incorporate charge. Understanding the correct formula for spherical capacitors is essential for solving the problem accurately.
swooshfactory
Messages
61
Reaction score
0

Homework Statement



I am trying to solve a question where I have three concentric metal shells at different radii. I am treating them as two capacitors in series. I would like to use the formula C= enot*area/distance between capacitors, but I have a few questions.



Homework Equations



(in next section)

The Attempt at a Solution



1. Which area would I use when computing the capacitance for between shells? I assume the smaller one, because I assume that if you put a small electrode over a larger electrode, the capacitor would only exist in the area between, making the smaller area the area to use.
2. Does this equation assume equal charge? No charge is used in the formula. However, the other formula I know for capacitance, C=Q/deltaV, would assume equal charge over both. Is this relevant for this problem?


Thanks for any help.
 
Physics news on Phys.org
HI swooshfactory,

swooshfactory said:

Homework Statement



I am trying to solve a question where I have three concentric metal shells at different radii. I am treating them as two capacitors in series. I would like to use the formula C= enot*area/distance between capacitors

This is the capacitance formula for a parallel-plate capacitor; a spherical capacitor would have a different formula. Once you find that formula (it should be in your textbook) you'll be able to answer your questions.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top