Concept of Distance and time. (basic question but no answer)

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The discussion revolves around a physics problem involving two cars, P and Y, approaching a finish line with different speeds and accelerations. Car P is 1 km away from the finish line, moving at 35 m/s with an acceleration of 0.4 m/s², while Car Y is 1.2 km away, traveling at 44 m/s with an acceleration of 0.5 m/s². The objective is to demonstrate that Car Y overtakes Car P 220 m before the finish line. Participants are attempting to apply the equations of motion but express confusion about the calculations and the concept of acceleration at the point of intersection. The conversation highlights the need for clarity in determining the distances each car must cover to reach the specified point before the finish line.
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Homework Statement


Car P is 1km from finish line with a speed of 35ms-1 and a uniform acceleration of 2/5ms-2
Car Y is 1.2km from finish line going at 44ms-1 and a uniform accelr of 1/2ms-1
show that Y passes p 220m before the finish line.

Homework Equations



v2=u2+2as
s=vt-1/2at^2

The Attempt at a Solution


so the acceleration when they are both in the same position is 0. thus i can use s=vt-1/2at^2 for both and cancel them out. so it would be 220=(44)t-(1/2)(1/2)t^2 for Y and for P it would be 220=(35)t-1/2(2/5)t^2. but then i end up with 0=9t-(1/20)t^2. then what? after that I'm lost.
 
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nabet94 said:
so the acceleration when they are both in the same position is 0.
How did you come up with this?

nabet94 said:
thus i can use s=vt-1/2at^2 for both and cancel them out. so it would be...

Why minus?

The problem states that you have to prove that car Y passes the car P 220 m before the finish line. What is the distance that each car has to pass in order to get to that position, i.e. 220 m before finish line?
 
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