Master replies:
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If sin(x)=sin(x') ,where x is some angle and x' a angle of another triangle, does it then follow that sin(x-90°)=sin(x'-90°)=cos(x)=cos(x')?
Not necessarily. There are identities covering for which angles the sine (and all the other trig functions) has the same value. If you don't want to look these up, you can draw the graph of y = sin (x) and pick them out (remember, sine is a periodic function).Master replies: said:More generally if the sinus of a angle is equivalent to another does that mean the angles are the same?
Like I said, you can look up the trig identities spelling out the details.Master replies: said:So is this true: sin(x)=sin(x')→sin(90°-x)=sin(90°-x')=cos(x)=cos(x')?
Master replies: said:I don't quite understand what you mean. If all I know is that sin(x)=sin(x') is it then also true that sin(90-x)=sin(90°-x'). I am sure it is. Do sines only differ by angle, as they only depend on the angle? Sorry if I repeat myself.
All of the trig functions are periodic, which means that two different angles can have the same sine (or cosine, tangent, etc.).Master replies: said:No I mean i don't understand what the trig identities have to do with my problem?
What you wrote is unintelligible. The period for some of the trig functions is ##2\pi##, so, for example, ##\sin(x + \pi) \ne \sin(x)##.Master replies: said:But only the angles in that only differ by a multiple of pi they are not compltly different.
What are not completely different?they are not compltly different.