Condition for a compound to be meso

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A compound is classified as meso if it possesses a plane of symmetry, which allows it to be superimposable on its mirror image. The discussion raises questions about the role of point symmetry or alternate axes of symmetry in determining if a compound can still be considered meso. Examples are requested to clarify these conditions further. The focus remains on understanding the specific symmetry requirements for meso compounds. Ultimately, the key condition for a compound to be meso is the presence of a plane of symmetry.
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Homework Statement


What should be the condition for a compound to be meso?


Homework Equations





The Attempt at a Solution


I know that it should possesses a plane of symmetry. But what if it contains a point of symmetry or alternate axis of symmetry instead of plane. Will the compound be called meso?
 
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utkarshakash said:

Homework Statement


What should be the condition for a compound to be meso?


Homework Equations





The Attempt at a Solution


I know that it should possesses a plane of symmetry. But what if it contains a point of symmetry...
Show me an example.
… or alternate axis of symmetry instead of plane. Will the compound be called meso?
Show me an example.
 
Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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