Condition for finite series: sum of squares finite + ?

mercedesbenz
Messages
14
Reaction score
0
Let u_n be a sequence of positive real number.
If \sum_{n=1}^{\infty}u_n^{2} finite + (condition??) then \sum_{n=1}^{\infty}u_n finite.
I want to find the condition.Please help me.
 
Physics news on Phys.org
Any obvious condition would be that (u_{n+1}/u_n)^2 not go to 1 as n goes to infinity. The only way \sum_{n=1}^{\infty}u_n^{2} can converge is if lim (u_{n+1}/u_n)^2\le 1. If lim (u_{n+1}/u_n)^2< 1 then lim u_{n+1}/u_n< 1 also and so \sum_{n=1}^{\infty}u_n converges. Of course, that is a sufficient condition, not a necessary condition. It is still possible that a sequence for which lim u_{n+1}/u_n\le 1 will converge.
 
Thank you so much,HallsofIvy. In my first post. you know, this is my ploblem which I've tried to do it for 1 month. Thank you again.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Back
Top