- #1

flemmyd

- 144

- 1

## Homework Statement

99% of all babies survive delivery. However, 10 % of all births involve Cesarean (C) sections, and when a C section is performed the baby survives 98% of the time. If a randomly chosen pregnant woman does not have a C section, what is the probability that her baby survives?

## Homework Equations

P(E) = 1 - P(E

^{C})

P(E U F) = P(E)+P(F)-P(EF)

P(E|F)=P(EF)/P(F)

## The Attempt at a Solution

P(S) = .99 for baby survival

P(C) = .1 for C section

P(S|C) = .98 for babies surviving the C section

P(S|C

^{C}) = ??

So I tried P(S|C

^{C}) =P(SC

^{C})/P(C

^{C})

I know the dominator = .9. I tried solving for the numerator using:

P(SC

^{C})= P(S)+P(C)-P(S U C), but at this point, I don't know what the P(S U C) is.