Conditions for Strict Inequality in Span Intersection

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Homework Statement


Let ##S_1## and ##S_2## be subsets of the vector space ##V##. Prove that ##span (S_1 \cap S_2) \subseteq span(S_1) \cap span(S_2)##. Given an examples of ##S_1## and ##S_2## for which equality holds and for which the inequality is strict.

Homework Equations

The Attempt at a Solution



I actually solved the problem written out in part 1--it was rather easy. But in the course of solving it, I wondered about the necessary and sufficient conditions for ##span(S_1) \cap span(S_2) \subseteq span(S_1 \cap S_2)##. I tried discovering them on my own, but this proved rather difficult. Are there any necessary and sufficient conditions?
 
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Bashyboy said:

Homework Statement


Let ##S_1## and ##S_2## be subsets of the vector space ##V##. Prove that ##span (S_1 \cap S_2) \subseteq span(S_1) \cap span(S_2)##. Given an examples of ##S_1## and ##S_2## for which equality holds and for which the inequality is strict.

Homework Equations

The Attempt at a Solution



I actually solved the problem written out in part 1--it was rather easy. But in the course of solving it, I wondered about the necessary and sufficient conditions for ##span(S_1) \cap span(S_2) \subseteq span(S_1 \cap S_2)##. I tried discovering them on my own, but this proved rather difficult. Are there any necessary and sufficient conditions?
Simply have a look on two lines in a (Euclidean) plane and discuss the possible cases.
 
Sorry to nitpick, but of course you want to avoid ## S_1=S_2 ##. And then you can do it analytically: If ##x \in S_1 \cap S_2 ## , then ## Span(S_1) \cap Span(S_2)## will contain ##Span {x_1}## , etc. Then try to find general form for element on ## Span(S_1) \cap Span(S_2)## that is not on the left.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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