Conducting sphere Find the electric filed for r<a,a<r<b,r>b

AI Thread Summary
The discussion focuses on calculating the electric field in different regions relative to a charged sphere. For the region where the radius r is between the inner radius a and outer radius b, the electric field E is zero. The key distinction lies in the use of enclosed charge: for r less than a, only the charge within that surface is considered, while for r greater than b, the total charge of the sphere is used. The participants clarify that Qenc represents the total charge enclosed by the integration surface. Understanding these concepts is crucial for accurately determining the electric field in various scenarios.
Jozefina Gramatikova
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Homework Statement



media%2Fd9f%2Fd9f8c6e6-1a34-41bc-b603-9b7c319db8c5%2FphpsMDTM3.png

Homework Equations



main-qimg-0984e30591a0778448038088e6a03223-c-jpg.jpg

The Attempt at a Solution


for part ii)
a<r<b E=0
I am not sure what will be the difference between the formulas for the electric field for a<r and a>b I think the formulas will look the same:
upload_2018-8-19_15-48-53.png

The only difference that I can think of is that when r<a, we are going to use the charge enclosed in that surface. For r>b we are going to use the total charge. Is that true?
 

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I'm confused on your use of variables, but looks like you got the right idea. You're correct, Qenc refers to total charge enclosed within the closed surface you're integrating over.
 
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