Engineering Conductor inside an electric motor current calculation

AI Thread Summary
To calculate the current flowing in a 500 mm conductor inside an electric motor, the force exerted on it is 1.5 Newtons and the magnetic flux density is 0.6 T. Using the formula F = B.I.L, where F is force, B is magnetic flux density, I is current, and L is length, the values are substituted into the equation. Rearranging gives I = F / (B * L), resulting in I = 1.5 / (0.6 * 0.5). The calculated current is 5 amps, confirming the solution is correct.
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Homework Statement



A 500 mm conductor inside an electric motor has a force of 1.5 Newtons exerted on it. If it is at right angles to a magnetic field of flux density 0.6 T, calculate the current flowing in the conductor.

Homework Equations



F=B.I.L

The Attempt at a Solution



B = 0.6T
F = 1.5N
L = 500mm = 0.5m
I =?1.5 = 0.6*I*0.5

I = 1.5/0.3= 5 amps.
 
Last edited:
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Looks right. :wink:
 

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