Confused on how to do a simple discrete math problem

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Homework Statement



Use the equivalence p\rightarrow(r \rightarrow s) \equiv p\wedge r\rightarrow s to rewrite the following problem before the proof.

Homework Equations



[p\rightarrow (q\rightarrow r)]\wedge (p\rightarrow q) \tautologicallyimplies (p\rightarrow r)


The Attempt at a Solution



[p\rightarrow (q\rightarrow r)]\wedge (p\rightarrow q) \tautologicallyimplies (p\rightarrow r)

1. p\rightarrow (q\rightarrow r) \equiv p\wedge q \rightarrow r \equiv \neg p \vee \neg q \vee r
2. p\rightarrow q \equiv \neg p \vee q

3. (\neg p \vee q)\wedge (\neg p \vee \neg q \vee r) \equiv ... \equiv p \rightarrow q\wedge r

What am I doing wrong?

Thanks!
 
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Does anyone know how to do this proof?
 
Go back to (p and q) -> r. What does p -> q say about the logical value of (p and q)?
 
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