Confused on the power through a Capacitor formula help

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The discussion centers on understanding the relationship between energy, power, and voltage in a capacitor circuit. The energy stored in a capacitor is given by the formula U = 1/2 CV², but confusion arises regarding how to derive power from this energy when it is treated as a constant. The conversation highlights the need for a time-dependent expression for voltage and energy, particularly after a switch closes at t = 0. It emphasizes that capacitance (C) is not the same as potential (V), and that the charge (Q) must be expressed as a function of time to analyze the circuit correctly. The correct approach involves using an exponential function to describe the voltage across the capacitor over time.
nchin
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I know that the energy stored in a capacitor is U = 1/2 CV2. but the power through it? I have in my notes that the power is the derivative of U.

so for example the energy is 26 Joules so the derivative of 26 J? doesn't make sense cause 26 is a constant.

help please!

i attached a picture of the problem. i first find the C equivalent.

oops! there's actually a switch on the top of the circuit! which closes at t = 0
 

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Can you find an expression for the potential across the equivalent capacitance with respect to time? How about the stored energy? This expression should be differentiable w.r.t. time...
 
gneill said:
Can you find an expression for the potential across the equivalent capacitance with respect to time? How about the stored energy? This expression should be differentiable w.r.t. time...

potential across is C = QV --> V(t) = C/Q(t). is that it?
 
nchin said:
potential across is C = QV --> V(t) = C/Q(t). is that it?

No. C is capacitance, not potential. C = QV is not a correct formula. And Q(t) does not provide any information about how the charge Q changes over time.

What is the expression for the voltage across the capacitance with respect to time for the given circuit? Hint: it involves an exponential function with a time constant.
 
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