Conic Parabolas in General Form

  • Thread starter Thread starter chaze
  • Start date Start date
  • Tags Tags
    Form General
AI Thread Summary
To analyze the conic parabola given by the equation y² - 8x + 4y + 12 = 0, the vertex, focus, axis of symmetry, directrix, direction, and value of p need to be determined. The discussion highlights the need to rearrange the equation to isolate the y terms and complete the square, transforming it into the standard form of a parabola. The standard forms indicate that the parabola opens left or right based on the sign of p, with the vertex at (h, k) and the focus located p units from the vertex along the axis of symmetry. Resources or tutorials for solving conic parabolas in general form are sought by the original poster. Understanding these concepts is essential for solving similar problems effectively.
chaze
Messages
1
Reaction score
0

Homework Statement



y2 - 8x + 4y + 12 = 0

I need to find the vertex, focus, axis of symmetry, directrix, direction and p.

Homework Equations



N/A

The Attempt at a Solution



No attempt as this is the first one I've encountered in general form. I'm not even looking for an answer, but if someone knows where to find a website or tutorial which helps in solving a conic parabola in this form then it would be very helpful.
 
Physics news on Phys.org
chaze said:

Homework Statement



y2 - 8x + 4y + 12 = 0

I need to find the vertex, focus, axis of symmetry, directrix, direction and p.

Homework Equations



N/A

The Attempt at a Solution



No attempt as this is the first one I've encountered in general form. I'm not even looking for an answer, but if someone knows where to find a website or tutorial which helps in solving a conic parabola in this form then it would be very helpful.
There are a couple of basic forms.
(y - k)2 = 4p(x - h)

(x - h)2 = 4p(y - k)

The first form above opens to the left or right, depending on whether p is negative or positive.

The second form opens down or up, depending on whether p is negative or positive.

In both, the vertex of the parabola is at (h, k), the focus is inside the parabola, and |p| units from the vertex, located on the axis of symmetry. The directrix is on the outside of the parabola, and |p| units the other way from the vertex.

For your problem, put the y terms on one side and the x terms on the other, and complete the square in the y terms. It should look like the first form above.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top