Conservation of angular momentum

AI Thread Summary
The discussion focuses on a system of four masses connected to a cross that spins on a smooth surface. When mass m4 disconnects, the conservation of momentum is initially applied to find the linear velocity of the remaining system. The calculated velocity after m4 detaches is v2 = Mω0L/(M+2m). Participants suggest using conservation of angular momentum to further analyze the system, noting the importance of determining the distances of each mass from the center of mass. The conversation emphasizes that the total energy of the system remains constant despite the detachment of m4.
phyyy
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Homework Statement


There's a system of 4 masses, all connected to a cross which has a negligible mass, and which is positioned on a smooth surface. The distance of each mass from the center of the cross is L and the cross spins around its center in a constant radial velocity of ω0 rad/sec:
dPcyf.gif

Now mass m4 disconnects from the cross.

What is the the radial velocity of the system after m4 disconnected, considering m1=m3 and m2=m4=M?

Homework Equations


Conservation of momentum:
Ʃmivi=0

Conservation of angular momentum:
Ʃmiviri=ωI

The Attempt at a Solution


I calculated using conservation of momentum that the linear velocity of the system after m4 disconnected was v2=Mω0L/(M+2m)

Now I think I should use the law of conservation of angular momentum but I'm not sure how. I think that the center of mass is L/2 to the right from the center of the cross so the distance of m1 and m3 from the center of mass is √((0.5L)2+L2). What should I do next?
 
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Relevant equations

Moment of Inertia =?
Angular Momentum=?
 
azizlwl said:
Relevant equations

Moment of Inertia =?
Angular Momentum=?

I know that the moment of inertia is I=Ʃmiri2 and the angular momentum L can be expressed as ωI, so I tried:

L=Ʃmiviri=ωI = ω(Ʃmiri2) and I can get the value of ω this way, but I'm not sure what the the distance from each mass to the center of mass is. I mean, what are the values of ri in this sum: Ʃmiri2 ?
 
phyyy said:

Homework Statement


There's a system of 4 masses, all connected to a cross which has a negligible mass, and which is positioned on a smooth surface. The distance of each mass from the center of the cross is L and the cross spins around its center in a constant radial velocity of ω0 rad/sec:
dPcyf.gif

Now mass m4 disconnects from the cross.

What is the the radial velocity of the system after m4 disconnected, considering m1=m3 and m2=m4=M?

Homework Equations


Conservation of momentum:
Ʃmivi=0

Conservation of angular momentum:
Ʃmiviri=ωI

The Attempt at a Solution


I calculated using conservation of momentum that the linear velocity of the system after m4 disconnected was v2=Mω0L/(M+2m)

Now I think I should use the law of conservation of angular momentum but I'm not sure how. I think that the center of mass is L/2 to the right from the center of the cross so the distance of m1 and m3 from the center of mass is √((0.5L)2+L2). What should I do next?
You have to start with conservation of energy.
All masses have equal tangential velocity.
As mass m4 detached from the cross(it follows a tangential path), the total energy of the system remains.

Using consevation of momentum requires the momentum of detached mass m4, which follows a straight line.
 
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