Conservation of energy and work

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Homework Help Overview

The problem involves a scenario where a man falls from a height and the discussion centers around calculating his speed just before impact and the average force exerted on him upon landing. The subject area relates to concepts of conservation of energy, work, and kinematics.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the calculation of the man's speed before impact and the subsequent force experienced during deceleration. There are questions about the appropriate equations to use and how to set up the problem for the second part regarding force.

Discussion Status

Some participants have provided insights into the necessary calculations and equations, while others are seeking clarification on the setup of the problem. There is an ongoing exploration of how to determine acceleration and the correct application of kinematic equations.

Contextual Notes

Participants are working within the constraints of the problem statement and are considering the implications of the given values, such as the height of the fall and the distance over which deceleration occurs.

Knfoster
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Homework Statement



A 70.4 kg man steps out of a window and falls (from rest) 1.33 m to a sidewalk. at is his speed just before his feet stke the pavement?

If the man falls with his knees and ankles locked, the only cushin for his fall is a 0.508 cm give in the pads of his feet. Calculate the erage force exerted on him bye ground in this situation. The avera force is sufficient to cause cartilage dage in the joints or to break bones.

Homework Equations



PE+KE=PE+KE (before and after)
W=F(xf-xi)cos theta
W=delta KE
PE=mgh
F=ma
KE=.5mv^2


The Attempt at a Solution



I already solved the first question and got 5.11 m/s.
I don't know how to set up the second problem to find the force.
Please help.
Thank you.
 
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I think they want you to calculate the force (acceleration) that will be required if the deceleration is over the space of just 1/2 cm (.508 cm).
 
ok. So F=ma, and I need to find acceleration to finish the problem. So Do I use Vf^2=Vi^2+2a(xf-xi) ? If so do I use 5.11 m/s for Vf and 0 m/s for Vo? Is xf=0 and xi=.508 cm?
 
Knfoster said:
ok. So F=ma, and I need to find acceleration to finish the problem. So Do I use Vf^2=Vi^2+2a(xf-xi) ? If so do I use 5.11 m/s for Vf and 0 m/s for Vo? Is xf=0 and xi=.508 cm?

Looks to me like what they are asking.
 

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