A ball is ikicked off a 100.0 m canyon at an angle of 30.0 degrees above the horizontal with a velocity of 24.0 m/s. What maximum height does it reach above the canyon floor?
WNC = KE + PE
The Attempt at a Solution
WNC = 1/2mvf^2 - 1/2mvi^2 + mghf - mghi
1/2mvi^2 + mghi = 1/2mvf^2 + mghf
I'm not sure what to do with the 30.0 degree angle?