Conservation of Energy Problem.

AI Thread Summary
The discussion revolves around solving a conservation of energy problem involving a 0.40 kg ball thrown at an angle. The key points include using the conservation of energy formula to find the speed at the highest point and the maximum height reached. At the highest point, the vertical velocity is zero while the horizontal velocity remains unchanged. The calculated height (y2) is 2.21 meters, derived from the energy conservation equation. The solution appears to be verified by participants in the thread.
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Here's the problem:

A .40 kg ball is thrown with a speed of 12m/s at an angle of 33 degrees. a) what is its speed at its highest point, and b) how high does it go? (Use conservat ionfo energy and ignore air resistance)

I think I'm supposed to use the formula .5mvi^2 + mgy1 = .5mvf^2+mgy2 .

How do I find the speed at the highest point? m=.4, and vi=12 right? Please help!
 
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A couple of hints:
What is the vertical velocity at its highest point?
Is the horizontal velocity at all affected during the flight?
 
At the highest point, vertical velocity is 0, and no, the horizontal velocity isn't affected... so then my final velocity would be zero, and y1 will be zero. This leaves me with 28.8-20 = (.40)(9.8)y2
y2 = 2.21 meters. Can anyone verify my answer?
 
Last edited:
Looks ok to me.
 

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