Conservation of energy / work problem

AI Thread Summary
The discussion revolves around clarifying a conservation of energy problem related to height differences in a hill scenario. Participants emphasize the importance of correctly identifying initial (yi) and final (yf) heights, which in this case is 30m and 0m, respectively. The confusion arises from algebraic simplifications and the need to factor terms in the equations presented. One participant confirms that the initial algebraic work is correct but suggests focusing on proper identification and factorization of terms to resolve the issue. Clear understanding of these steps is essential for solving the problem accurately.
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Homework Statement
Call the system the bicycle and the rider. Use the work-energy equation and W = Fd. Assume the cyclist and air do not heat up. The work-energy equation is Kf + Ugf = Ki + Ugi + W.
Relevant Equations
Kinetic energy & gravitational energy
Answer- Physics .jpg
Attempt 1- Physics.jpg
Attempt 2- Physics.jpg

If someone could advise what I've done wrong it would be much appreciated. How have they eliminated the initial and final for y, and simplify only to y? Also, how did they simplify to a positive 2? What algebraic steps have I missed? Thanks for your help.
 
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I would not call that a problem statement. What is the actual question?
 
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haruspex said:
I would not call that a problem statement. What is the actual question?
695672E7-6A77-4F8D-8425-24ED89C62321.png


Sorry here it is. Question 9. Thanks!
 
You are told the top of the hill is 30m higher than the bottom of the hill. So what is yi-yf?
 
haruspex said:
You are told the top of the hill is 30m higher than the bottom of the hill. So what is yi-yf?

30m-0m.

Is this how I went wrong when solving algebraically in the image of my working?
 
There was nothing wrong in what you worked out. As haruspex pointed out, identify yi and yf in your own algebra and you are done.
 
adams_695 said:
30m-0m.

Is this how I went wrong when solving algebraically in the image of my working?
The last line of your working has the terms -2gyf+2gyi. Factorise.
 
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