A stone is thrown upward at an angle of 53 degrees above the horizontal. Its maximum height above the release point is 24m. What was the stone's initial speed?(adsbygoogle = window.adsbygoogle || []).push({});

Assume any effects of air resistance are negligible.

This problem is to be solved using Conservation of Energy.

Since there is no external force nor non-conservative forces present, this is just the change in mechanical energy.

Uf + Kf = Ui + Ki

mgh + 0 = 0 + 1/2 mv^2

=mgh = 1/2 mv^2

where y = 0 at the horizontal.

I got stuck because the mass of the stone is not given. Is my approach wrong?

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# Homework Help: Conservation of Energy

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