Conservation of engery and work 2.

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Ben carries a 200N suitcase up three flights of stairs, covering a vertical distance of 10.0m, and then pushes it with a horizontal force of 50.0N across 35.0m on the third floor. The total work done by Ben is calculated using the formula mgh + F*s, resulting in 3750 Joules. There was confusion regarding the inclusion of gravity in the calculations, but 200N already accounts for gravitational force. The velocity provided in the problem is not necessary for calculating work in this context. The discussion emphasizes the importance of using correct units and understanding the relationship between force, distance, and work.
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ben carries a 200N suitcase up three flights of stairs total vertical distance of 10.0m and then pushes the suitcase with a horizontal force of 50.0 N at a constant speed of 50 m s for a horizontal of 35.0 m across the 3rd floor how much work does Ben do on the suitcase during this entire motion

Total work done by Ben = mgh + F*s = 200 * 10 + 50 *35 = 2000 + 1750 = 3750 Joules.

i have a feeling this is wrong i really need help!
 
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Ereny said:
ben carries a 200N suitcase up three flights of stairs total vertical distance of 10.0m and then pushes the suitcase with a horizontal force of 50.0 N at a constant speed of 50 m s for a horizontal of 35.0 m across the 3rd floor how much work does Ben do on the suitcase during this entire motion

Total work done by Ben = mgh + F*s = 200 * 10 + 50 *35 = 2000 + 1750 = 3750 Joules.

i have a feeling this is wrong i really need help!

That's close. You left out the acceleration of gravity when you plugged in the numbers.

It helps to carry units along in your equations -- if you had, you would have noticed that the units were not Joules when you calculated just mh instead of mgh.

Try again (with units this time)?
 
yeah well 200 n includes the 9.81 so i don't need to include it again right?
 
Ereny said:
yeah well 200 n includes the 9.81 so i don't need to include it again right?

Whoops! You are right!
 
okay so here's what i did

200N x 10m + 50 N x .5om/s = 2025
 
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and i think i typed the velocity wrong in the question is should be .50 m/s
 
Ereny said:
okay so here's wt i did

200N x 10m + 50 N x .5om/s = 2025

No, you had it right the first time. When pushing the object, the work is force X distance. The units of work are Newtons * meters, not Nm/s.
 
ohh kk .. why did they give me the velocity then.. doesn't that mean i have to use it?
 
Ereny said:
ohh kk .. why did they give me the velocity then.. doesn't that mean i have to use it?

Nope. Not to answer the question they gave you.
 
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