Conservation of Momentum and Kinetic Energy in Inelastic Collisions

AI Thread Summary
In an inelastic collision involving a 50g object moving at 0.3 m/s and a 100g object at 0.25 m/s, momentum is conserved while kinetic energy is not. The final velocity after the collision is calculated to be 4/15 m/s. The initial kinetic energy is found to be 0.005375 J, while the final kinetic energy is 0.005333 J, resulting in a loss of 0.000042 J. The discussion emphasizes the importance of understanding the principles behind energy calculations, particularly the interpretation of negative values in energy loss. Overall, grasping the concepts of momentum and energy conservation is crucial for solving such problems accurately.
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Homework Statement


A 50g object is moving east at 0.3 m/s. A 100g object is moving east as well at 0.25 m/s. These objects have an inelastic collision.

a) Find their final velocity
b) Find the kinetic energy lost

Homework Equations


P1 + P2 = P3 + P4 ; momentum is conserved
Ek = 1/2 mv^2

The Attempt at a Solution


So the only thing conserved is momentum

Please excuse me for not using units, it's too confusing to do that on a keyboard.

a) (0.3 * 50/1000 + 0.25 * 100/1000) / (150/1000) = vf = 4 / 15 m/s

b) Ek1 = 0.5 * (50/1000) * 0.3^2 + 0.5 * (100/1000) * 0.25^2 = 0.005375 J
Ek2 = 0.5 * (50/1000) * (4/15)^2 + 0.5 * (100/1000) * (4/15)^2= 0.00533333333J

Ek1 - Ek2 = 0.000042 J

Is this correct? Someone said that its Ek2 - Ek1 but that doesn't make sense to me, because then delta(Ek) would be negative and this is impossible. Also, 10 marbles - 3 marbles. 7 were lost
 
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Strictly speaking, ##\Delta E## of the system is negative; there's nothing wrong with that. The negative sign corresponds to a loss of energy. ##\Delta E## is defined as ##E_{f} - E_{i}##

If you want to phrase it in terms of energy lost, then simply take the absolute value when intepreting the answer. It's generally not good practice to nudge your answer into a positive value "by hand" as the sign carries physical meaning (and it also confuses you - subtract which from which?)
 
Fightfish said:
Strictly speaking, ##\Delta E## of the system is negative; there's nothing wrong with that. The negative sign corresponds to a loss of energy. ##\Delta E## is defined as ##E_{f} - E_{i}##

If you want to phrase it in terms of energy lost, then simply take the absolute value when intepreting the answer. It's generally not good practice to nudge your answer into a positive value "by hand" as the sign carries physical meaning (and it also confuses you - subtract which from which?)

Ah I see, but isn't Einitial - Efinal also correct?
 
It gives you the answer you wanted in this case, but I emphasize that understanding general principle(s) and idea(s) is more important. That is, it is perfectly fine to use so-called "shortcuts" like this while solving problems, but it is essential to know what exactly you are doing when you use them.
 
Fightfish said:
It gives you the answer you wanted in this case, but I emphasize that understanding general principle(s) and idea(s) is more important. That is, it is perfectly fine to use so-called "shortcuts" like this while solving problems, but it is essential to know what exactly you are doing when you use them.

Okay, thank you for the advice. I think that I will try harder to understand the principals.
 
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