Conservation of Momentum in a explosion

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In the discussion about the conservation of momentum during a firecracker explosion, it is established that momentum is conserved. The first fragment, with a mass of 14g, moves at 48m/s in the positive x direction. The second fragment's mass is calculated to be 41g, moving in the negative x direction to ensure the total momentum remains zero. The key point is that the initial momentum is zero, and thus the momenta of the two fragments must cancel each other out. This reinforces the principle that in an isolated system, the total momentum before and after an event remains constant.
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Homework Statement


A firecracker, initially at rest, explodes into two fragments. The first, of mass 14g, moves in the positive x direction at 48m/s. The second moves at 32m/s. Find the mass and direction of its motion.


Homework Equations


p=mv


The Attempt at a Solution



So I know momentum is conserved in this situation. I set m1v1 equal to m2v2 and found the mass of the second fragment to be .041 kg or 41 grams. I think this goes in the negative x direction because the initial momentum is zero and so the sum of all momentums would have to be zero, but I am not sure.
 
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mvl46566 said:

Homework Statement


A firecracker, initially at rest, explodes into two fragments. The first, of mass 14g, moves in the positive x direction at 48m/s. The second moves at 32m/s. Find the mass and direction of its motion.


Homework Equations


p=mv


The Attempt at a Solution



So I know momentum is conserved in this situation. I set m1v1 equal to m2v2 and found the mass of the second fragment to be .041 kg or 41 grams. I think this goes in the negative x direction because the initial momentum is zero and so the sum of all momentums would have to be zero, but I am not sure.
Correct. In the conservation of momentum, the momentum after the explosion = momentum before the explosion. What is the momentum before the explosion?

Remember that momentum is a vector, which has magnitude and direction. We can have to vectors of the same magnitude, but opposite direction, so the sum is zero.
 

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