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Homework Statement
Ball One: 0.4 kg, energy 100J before collision.
Ball Two: 0.6 kg, energy 112J before collision.
Two balls are thrown at each other and collide in midair. Ball Two flies off at an angle 32º below the horizontal with an energy of 95J. At what angle and speed did Ball One move away from the collision?
Homework Equations
Conservation of momentum, conservation of kinetic energy.
KE=1/2*m*v^2
The Attempt at a Solution
I have no idea how to find the angle of deflection, but I thought I could get the velocity of the ball as follows:
The total kinetic energy in the system should be conserved, so KE1i+KE2i = KE tot
KEtot-KE2f = KE1f = 1/2*m1*v1f^2
v1f = sqrt (2KE1f/m1) = sqrt (2*(222-95)/0.4) = 25.1 m/s
The answer in the back of the book is 20 m/s, 40º above the horizontal. Keep in mind, this is a first edition textbook, so answers are often incorrect. Any suggestions?
Thanks :)