Let me try from a slightly different angle.
We have a 10-parameter Poincar'e group of inertial transformations for which the relativity principle can be applied. This group should be represented by unitary operators in the Hilbert space of any isolated quantum system. The 10 independent generators of this representation are Hermitian operators, which we identify with total observables of the system. They are the Hamiltonian ##H##, the total momentum vector ##\boldsymbol{P}##, the total angular momentum vector ##\boldsymbol{J}##, and the boost operator ##\boldsymbol{K}##.
From commutation relations of the Poincar'e Lie algebra, we can find out how the above total observables transform with respect to time translations. The first three operators commute with the Hamiltonian ##[H,H]=[\boldsymbol{P}, H] = [\boldsymbol{J}, H]=0##, so we get the 7 conservation laws immediately. We can also define an operator
##\boldsymbol{V} \equiv \boldsymbol{P}c^2/H##, (1)
call it "velocity," and verify that it is conserved. But at this point there is nothing relating this operator to the observable of position. Some extra logical steps have to be taken to establish this relationship.
Now we turn our attention to the boost operator, which does not commute with the Hamiltonian: ##[\boldsymbol{K}, H] = -i \hbar \boldsymbol{P}##. This means that, strictly speaking, there is no conservation law associated with boosts. However, ##\boldsymbol{K}## depends on time linearly
##\boldsymbol{K}(t) = \boldsymbol{K}(0) + \boldsymbol{P}t##, (2)
so we can say that there is an independent law stating that "the center-of-mass ##\boldsymbol{K}## is moving uniformly."
Now, it is not common to use the boost observable ##\boldsymbol{K}## in physics. Traditionally, we use the better known "center-of-mass position", which is related to the boost observable by formula ##\boldsymbol{R} \equiv - \boldsymbol{K}c^2/H##. (This is the famous Newton-Wigner formula, where I omitted spin contributions for simplicity and pretended that ##\boldsymbol{K}## and ##H## commute.) Only now we can use eqs. (1) and (2) and confidently say that the center-of-mass position of any physical system moves uniformly and that the rate of this motion is given by the (conserved) velocity operator introduced earlier
##\boldsymbol{R}(t) = \boldsymbol{R}(0) + \boldsymbol{V}t##
I hope this answers your original question about the conservation law associated with boosts.
Eugene.