- #1

majinkenji

- 8

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For the phase shift, we would use (-c/b); which aligns with the original function equation and makes sense to me.

But in the case of a trig function such as: y = A cos (-bx + c)

For the phase shift, we would use (+c/-b); which would be a negative phase shift instead of the positive phase shift. This is probably because my school just gave us a mechanism for phase shift of simply dividing c by b. But doing this:

-bx + c = 0 -> x = -c/-b -> is this legal algebraically?

Seems to be different answer, +c which would align with the function. (y = A cos (-bx + c))

In the case of a negative B and a positive C, could I just put it together like y = [-b(x-(-c))] and use the standard c/b type approach?

Any help in 'visualizing' this problem would be greatly appreciated.

Thanks so much for your patience.

mk