- #1
majinkenji
- 8
- 0
Consider a trig function such as: y = A cos (bx - c)
For the phase shift, we would use (-c/b); which aligns with the original function equation and makes sense to me.
But in the case of a trig function such as: y = A cos (-bx + c)
For the phase shift, we would use (+c/-b); which would be a negative phase shift instead of the positive phase shift. This is probably because my school just gave us a mechanism for phase shift of simply dividing c by b. But doing this:
-bx + c = 0 -> x = -c/-b -> is this legal algebraically?
Seems to be different answer, +c which would align with the function. (y = A cos (-bx + c))
In the case of a negative B and a positive C, could I just put it together like y = [-b(x-(-c))] and use the standard c/b type approach?
Any help in 'visualizing' this problem would be greatly appreciated.
Thanks so much for your patience.
mk
For the phase shift, we would use (-c/b); which aligns with the original function equation and makes sense to me.
But in the case of a trig function such as: y = A cos (-bx + c)
For the phase shift, we would use (+c/-b); which would be a negative phase shift instead of the positive phase shift. This is probably because my school just gave us a mechanism for phase shift of simply dividing c by b. But doing this:
-bx + c = 0 -> x = -c/-b -> is this legal algebraically?
Seems to be different answer, +c which would align with the function. (y = A cos (-bx + c))
In the case of a negative B and a positive C, could I just put it together like y = [-b(x-(-c))] and use the standard c/b type approach?
Any help in 'visualizing' this problem would be greatly appreciated.
Thanks so much for your patience.
mk