Constant angular acceleration of a rotating wheel

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To find the constant angular acceleration of a rotating wheel that takes 4.7 seconds to complete 33.5 revolutions and reaches an angular speed of 45.5 rad/s, the initial angular velocity must be determined first, as it is not provided. The equation wf^2 - wo^2 = 2a(θf - θo) can be applied, where wf is the final angular velocity, wo is the initial angular velocity, and θ represents angular displacement. Since the initial angular velocity cannot be assumed to be zero, a standard constant acceleration formula should be utilized to solve for angular acceleration. The discussion emphasizes the need to clarify initial conditions before proceeding with calculations. Understanding these variables is crucial for accurately determining the angular acceleration in rad/s².
jscherf92
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A rotating wheel requires 4.7 s to rotate
through 33.5 rev. Its angular speed at the
end of the 4.7 s interval is 45.5 rad/s.
What is its constant angular acceleration?
Assume the angular acceleration has the same
sign as the angular velocity.
Answer in units of rad/s2.

wf^2-wo^2=2a(Of-Oo)

Ive got a page of failed equations on my paper, and i need a push in the right direction.
 
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Hi jscherf92! :smile:

The question doesn't give you the initial angular velocity, so I don't think we can assume it's zero.

So use a standard constant acceleration formula with s t a and v (angular version) :wink:
 

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