Constant angular acceleration problem

[saturn67]

how to Divide these two equations to get a cancel ?

 

[rl.bhat]

2pi/4pi = 1/2*a*t^2/1/2a*(t+0.48)^2
1/2 = t^2/(t+0.48)^2
solve for t

 

[saturn67]

that give t=0.48
which it like not solving anything :(

 

[rl.bhat]

Cross multiplying the above expression we get (t + 0.48 )^2 = 2t^2
Taking sqrt. on both side we get t + 0.48 = 1.41t or 0.41t = 0.48 or t = 0.48/0.41

 

[saturn67]

woot u were right
LOL stupid me
thank you