Constant energy in an elliptical orbit

Click For Summary
SUMMARY

The total mechanical energy E of a mass in an elliptical orbit is defined by the equation E = (1/2)μ(dr/dt)² + (1/2)(angular momentum)² / μr² - GMm/r. At both the apogee and perigee, the radial kinetic energy is zero, yet the radius r differs, raising the question of how energy remains constant. The key insight is that r appears in the denominator of two terms with opposite signs, balancing the energy equation despite changes in radius.

PREREQUISITES
  • Understanding of elliptical orbits and their properties
  • Familiarity with the concepts of kinetic and potential energy
  • Knowledge of angular momentum in orbital mechanics
  • Basic grasp of gravitational forces and the reduced mass concept
NEXT STEPS
  • Study the principles of conservation of mechanical energy in orbital mechanics
  • Explore the derivation of the equations governing elliptical orbits
  • Learn about the implications of varying radius in orbital dynamics
  • Investigate the role of angular momentum in maintaining orbital stability
USEFUL FOR

Students of physics, particularly those studying mechanics and orbital dynamics, as well as educators looking to clarify concepts related to energy conservation in elliptical orbits.

Sleepycoaster
Messages
17
Reaction score
0

Homework Statement



There's no specific question, but mostly a theory I wanted clarified. According to my textbook, the measurement of the total mechanical energy E of a mass orbiting a much larger mass in an ellipse is:

E = radial (change in radius) kinetic energy + rotational kinetic energy + potential energy

Or in other words,

E = (1/2)μ(dr/dt)2 + (1/2)(angular momentum)^2 / μr2 - GMm/r

But consider this: At both the apogee and perigee of the orbit the total energy should be constant and radial kinetic energy should be zero. Yet at these points the r is different and everything else is the same. How can energy be constant?

Homework Equations



r is the radius between the focus of the ellipse where the larger mass is and the smaller mass
μ is the reduced mass 1/(1/m + 1/M)

The Attempt at a Solution



None so far. It seems like a rather fundamental issue with a hopefully fundamental fix.
 
Last edited:
Physics news on Phys.org
Hello, sleepycoaster.

Sleepycoaster said:
E = (1/2)μ(dr/dt)2 + (1/2)(angular momentum)^2 / μr2 - GMm/r

But consider this: At both the apogee and perigee of the orbit the total energy should be constant and radial kinetic energy should be zero.

Yes.

Yet at these points the r is different and everything else is the same. How can energy be constant?

Note that r occurs in the denominator of two terms and the two terms have opposite signs.
 
  • Like
Likes   Reactions: 1 person

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 30 ·
2
Replies
30
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 13 ·
Replies
13
Views
1K
Replies
5
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K