- #1
saadsarfraz
- 86
- 1
constructible angles-->help please
x=2(pi)/7 we will show that this is not constructible and therefore 7-gon is not constructible.
a) show cos4x = cos3x
b) Use the above equation to find a rational quartic polynomial f(y)
where f(cos x) = 0.
c)From f, find a cubic rational polynomial g(y) where g(cos x) = 0
see above
im having trouble in part b). i expanded cos4x - cos3x = 0 in terms of cos(x) and I made the substitution y= cos(x) i got the quartic equation 8y^4 + 4y^3 - 8y^(2) -3y + 1 =0.
but when i put y= cos(2(pi)/7)) it dosent come out to 0.
Homework Statement
x=2(pi)/7 we will show that this is not constructible and therefore 7-gon is not constructible.
a) show cos4x = cos3x
b) Use the above equation to find a rational quartic polynomial f(y)
where f(cos x) = 0.
c)From f, find a cubic rational polynomial g(y) where g(cos x) = 0
Homework Equations
see above
The Attempt at a Solution
im having trouble in part b). i expanded cos4x - cos3x = 0 in terms of cos(x) and I made the substitution y= cos(x) i got the quartic equation 8y^4 + 4y^3 - 8y^(2) -3y + 1 =0.
but when i put y= cos(2(pi)/7)) it dosent come out to 0.