Constructive and Destructive Interference of Waves at pi/50 Time - Find Points

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The discussion focuses on finding points of constructive and destructive interference for the given wave functions y1 and y2 at t=pi/50. The user attempts to derive conditions for interference by equating the derivatives of the combined wave functions but struggles to find a clear path to the solution. The known results indicate that constructive interference occurs at x=pi/60 + 2pi n/30, while destructive interference occurs at x=n pi/30. The user acknowledges the relationship between the waves' amplitudes and angular frequencies, noting that constructive interference results in doubled amplitude and destructive interference results in cancellation. The conversation emphasizes understanding phase relationships to solve the problem effectively.
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Homework Statement


y1(x,t)=4*cos(20*t-30*x)
y2(x,t)=4*cos(20*t+30*x)
set t=pi/50 and find the points where the wave interferes constructively and destructively

The Attempt at a Solution



So I tried to take the derivative of y1 and y2 added together and set it equal to zero.

120*sin(\frac{2 \pi}{5}-30x) = 120*sin(\frac{2 \pi}{5}+30x)

then I took out the 120 on both sides, but I am not sure what to do from their exactly. I tried to take the arcsin a few different ways but I couldn't get anything concrete.

I know the answer is x= \frac{\pi}{60}+\frac{2 \pi n}{30} for constructive
and x= \frac{n \pi}{30} for destructive

this makes sense to me since the period would be 2pi/30 but I don't get how they actually got there. Could someone point me in the right direction
 
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Since both of these waves have the same amplitude and the same angular frequency when they interfere they will give 0 for destructive interference and wave*2 for constructive.

wave1 + wave2 = 0 happens when?

how does the constructive go?

think about what a phase really means
 
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